백준[Java] 10998번 AXB

https://www.acmicpc.net/problem/10998

10998번: A×B

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문제풀이

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int A = sc.nextInt();
        int B = sc.nextInt();
        System.out.println(A*B);
        sc.close();
    }
}

• 백준 1000문제와 같이 풀어주면 됨
• 사칙연산 문제이기 때문에 간단한 문제

주의사항

• 공백 단위로 입력해야함

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문제풀이 2

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        String str = br.readLine();

        StringTokenizer st = new StringTokenizer(str, " ");
        int A = Integer.parseInt(st.nextToken()); // st.nextToken() 은 문자열을 반환하니 Integer.parseInt()로 int 형으로 변환
        int B = Integer.parseInt(st.nextToken());

        System.out.println(A*B);
    }
}

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문제풀이 3

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class _10998_3 {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        StringTokenizer st = new StringTokenizer(br.readLine(), " ");
        int A = Integer.parseInt(st.nextToken()); // st.nextToken() 은 문자열을 반환하니 Integer.parseInt()로 int 형으로 변환
        int B = Integer.parseInt(st.nextToken());

        System.out.println(A*B);
    }
}

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문제풀이 4

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class _10998_4 {
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

        String[] str = br.readLine().split(" ");
        int A = Integer.parseInt(str[0]);
        int B = Integer.parseInt(str[1]);

        System.out.println(A*B);
    }
}